Understanding IP Addressing: Everything You Ever Wanted To Know

Appendix D – VLSM Example

VLSM Exercise
Given
An organization has been assigned the network number 140.25.0.0/16 and it plans to deploy VLSM. Figure C-1 provides a graphic display of the VLSM design for the organization.

Figure C-1: Address Strategy for VLSM Example

To arrive at this design, the first step of the subnetting process divides the base network address into 8 equal-sized address blocks. Then Subnet #1 is divided it into 32 equal-sized address blocks and Subnet #6 is divided into 16 equal-sized address blocks. Finally, Subnet #6-14 is divided into 8 equal-sized address blocks.

1. Specify the eight subnets of 140.25.0.0/16:
#0 ________________________________________________________________
#1 ________________________________________________________________
#2 ________________________________________________________________
#3 ________________________________________________________________
#4 ________________________________________________________________
#5 ________________________________________________________________
#6 ________________________________________________________________
#7 ________________________________________________________________

2. List the host addresses that can be assigned to Subnet #3 (140.25.96.0):
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________

3. Identify the broadcast address for Subnet #3 (140.25.96.0):
__________________________________________________________________

4. Specify the 16 subnets of Subnet #6 (140.25.192.0/19):
#6-0_______________________________________________________________
#6-1_______________________________________________________________
#6-2_______________________________________________________________
#6-3_______________________________________________________________
#6-4_______________________________________________________________
#6-5_______________________________________________________________
#6-6_______________________________________________________________
#6-7_______________________________________________________________
#6-8_______________________________________________________________
#6-9_______________________________________________________________
#6-10______________________________________________________________
#6-11______________________________________________________________
#6-12______________________________________________________________
#6-13______________________________________________________________
#6-14______________________________________________________________
#6-15______________________________________________________________

5. List the host addresses that can be assigned to Subnet #6-3 (140.25.198.0/23):
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________

6. Identify the broadcast address for Subnet #6-3 (140.25.198.0/23):
__________________________________________________________________

7. Specify the eight subnets of Subnet #6-14 (140.25.220.0/23):
#6-14-0 ____________________________________________________________
#6-14-1 ____________________________________________________________
#6-14-2 ____________________________________________________________
#6-14-3 ____________________________________________________________
#6-14-4 ____________________________________________________________
#6-14-5 ____________________________________________________________
#6-14-6 ____________________________________________________________
#6-14-7 ____________________________________________________________

8. List the host addresses that can be assigned to Subnet #6-14-2 (140.25.220.128/26):
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________
__________________________________________________________________

9. Identify the broadcast address for Subnet #6-14-2 (140.25.220.128/26):
__________________________________________________________________

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Solution for VLSM Exercise
1. Specify the eight subnets of 140.25.0.0/16:

Base Network: 10001100.00011001 .00000000.00000000 = 140.25.0.0/16
Subnet #0: 10001100.00011001. 000 00000.00000000 = 140.25.0.0/19
Subnet #1: 10001100.00011001. 001 00000.00000000 = 140.25.32.0/19
Subnet #2: 10001100.00011001. 010 00000.00000000 = 140.25.64.0/19
Subnet #3: 10001100.00011001. 011 00000.00000000 = 140.25.96.0/19
Subnet #4: 10001100.00011001. 100 00000.00000000 = 140.25.128.0/19
Subnet #5: 10001100.00011001. 101 00000.00000000 = 140.25.160.0/19
Subnet #6: 10001100.00011001. 110 00000.00000000 = 140.25.192.0/19
Subnet #7: 10001100.00011001. 111 00000.00000000 = 140.25.224.0/19

2. List the host addresses that can be assigned to Subnet #3 (140.25.96.0)
Subnet #3: 10001100.00011001.011 00000.00000000 = 140.25.96.0/19
Host #1: 10001100.00011001.011 00000.00000001 = 140.25.96.1/19
Host #2: 10001100.00011001.011 00000.00000010 = 140.25.96.2/19
Host #3: 10001100.00011001.011 00000.00000011 = 140.25.96.3/19
.
.
Host #8189: 10001100.00011001.011 11111.11111101 = 140.25.127.253/19
Host #8190: 10001100.00011001.011 11111.11111110 = 140.25.127.254/19

3. Identify the broadcast address for Subnet #3 (140.25.96.0)
10001100.00011001.011 11111.11111111 = 140.25.127.255

4. Specify the 16 subnets of Subnet #6 (140.25.192.0/19):
Subnet #6: 10001100.00011001.110 00000.00000000 = 140.25.192.0/19
Subnet #6-0: 10001100.00011001.110 00000.00000000 = 140.25.192.0/23
Subnet #6-1: 10001100.00011001.110 00010.00000000 = 140.25.194.0/23
Subnet #6-2: 10001100.00011001.110 00100.00000000 = 140.25.196.0/23
Subnet #6-3: 10001100.00011001.110 00110.00000000 = 140.25.198.0/23
Subnet #6-4: 10001100.00011001.110 01000.00000000 = 140.25.200.0/23
.
.
Subnet #6-14: 10001100.00011001.110 11100.00000000 = 140.25.220.0/23
Subnet #6-15: 10001100.00011001.110 11110.00000000 = 140.25.222.0/23

5. List the host addresses that can be assigned to Subnet #6-3 (140.25.198.0/23):
Subnet #6-3: 10001100.00011001.1100011 0.00000000 = 140.25.198.0/23
Host #1 10001100.00011001.11000110.00000001 = 140.25.198.1/23
Host #2 10001100.00011001.1100011 0.00000010 = 140.25.198.2/23
Host #3 10001100.00011001.1100011 0.00000011 = 140.25.198.3/23
Host #4 10001100.00011001.1100011 0.00000100 = 140.25.198.4/23
Host #5 10001100.00011001.1100011 0.00000110 = 140.25.198.5/23
.
.
Host #509 10001100.00011001.1100011 1.11111101 = 140.25.199.253/23
Host #510 10001100.00011001.1100011 1.11111110 = 140.25.199.254/23

6. Identify the broadcast address for Subnet #6-3 (140.25.198.0/23)
10001100.00011001.1100011 1.11111111 = 140.25.199.255

7. Specify the eight subnets of Subnet #6-14 (140.25.220.0/23):
Subnet #6-14: 10001100.00011001.1101110 0.00000000 = 140.25.220.0/23
Subnet#6-14-0: 10001100.00011001.1101110 0.00 000000 = 140.25.220.0/26
Subnet#6-14-1: 10001100.00011001.1101110 0.01 000000 = 140.25.220.64/26
Subnet#6-14-2: 10001100.00011001.1101110 0.10 000000 = 140.25.220.128/26
Subnet#6-14-3: 10001100.00011001.1101110 0.11 000000 = 140.25.220.192/26
Subnet#6-14-4: 10001100.00011001.1101110 1.00 000000 = 140.25.221.0/26
Subnet#6-14-5: 10001100.00011001.1101110 1.01 000000 = 140.25.221.64/26
Subnet#6-14-6: 10001100.00011001.1101110 1.10 000000 = 140.25.221.128/26
Subnet#6-14-7: 10001100.00011001.1101110 1.11 000000 = 140.25.221.192/26

8. List the host addresses that can be assigned to Subnet #6-14-2 (140.25.220.128/26):
Subnet#6-14-2: 10001100.00011001.11011100.10 000000 = 140.25.220.128/26
Host #1 10001100.00011001.11011100.10 000001 = 140.25.220.129/26
Host #2 10001100.00011001.11011100.10 000010 = 140.25.220.130/26
Host #3 10001100.00011001.11011100.10 000011 = 140.25.220.131/26
Host #4 10001100.00011001.11011100.10 000100 = 140.25.220.132/26
Host #5 10001100.00011001.11011100.10 000101 = 140.25.220.133/26
.
.
Host #61 10001100.00011001.11011100.10 111101 = 140.25.220.189/26
Host #62 10001100.00011001.11011100.10 111110 = 140.25.220.190/26

9. Identify the broadcast address for Subnet #6-14-2 (140.25.220.128/26):
10001100.00011001.11011100.10 111111 = 140.25.220.191

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